14113133311335 has 16 divisors (see below), whose sum is σ = 22628155299840. Its totient is φ = 7511290432160.

The previous prime is 14113133311267. The next prime is 14113133311351. The reversal of 14113133311335 is 53311333131141.

It is not a de Polignac number, because 14113133311335 - 2¹² = 14113133307239 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14113133311296 and 14113133311305.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 982117611 + ... + 982131980.

It is an arithmetic number, because the mean of its divisors is an integer number (1414259706240).

Almost surely, 2^{14113133311335} is an apocalyptic number.

14113133311335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

14113133311335 is a deficient number, since it is larger than the sum of its proper divisors (8515021988505).

14113133311335 is a wasteful number, since it uses less digits than its factorization.

14113133311335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1964250078.

The product of its digits is 14580, while the sum is 33.

Adding to 14113133311335 its reverse (53311333131141), we get a palindrome (67424466442476).

The spelling of 14113133311335 in words is "fourteen trillion, one hundred thirteen billion, one hundred thirty-three million, three hundred eleven thousand, three hundred thirty-five".