Base | Representation |
---|---|
bin | 1000001101110000010… |
… | …1010101100100001001 |
3 | 111111021200111220112012 |
4 | 2003130011111210021 |
5 | 4303014110340131 |
6 | 144500154225305 |
7 | 13124236411526 |
oct | 2033405254411 |
9 | 444250456465 |
10 | 141131340041 |
11 | 54942a6470a |
12 | 23428725235 |
13 | 10402096883 |
14 | 6b8b9a814d |
15 | 3a101e852b |
hex | 20dc155909 |
141131340041 has 8 divisors (see below), whose sum is σ = 144729487584. Its totient is φ = 137547557280.
The previous prime is 141131340011. The next prime is 141131340047. The reversal of 141131340041 is 140043131141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141131340041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 141131339989 and 141131340016.
It is not an unprimeable number, because it can be changed into a prime (141131340047) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3571295 + ... + 3610596.
It is an arithmetic number, because the mean of its divisors is an integer number (18091185948).
Almost surely, 2141131340041 is an apocalyptic number.
It is an amenable number.
141131340041 is a deficient number, since it is larger than the sum of its proper divisors (3598147543).
141131340041 is an equidigital number, since it uses as much as digits as its factorization.
141131340041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7182391.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 141131340041 its reverse (140043131141), we get a palindrome (281174471182).
The spelling of 141131340041 in words is "one hundred forty-one billion, one hundred thirty-one million, three hundred forty thousand, forty-one".
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