Base | Representation |
---|---|
bin | 100000000101101110110011… |
… | …100000100101011111101000 |
3 | 200111201000122212220001202111 |
4 | 200011232303200211133220 |
5 | 121444243442030334422 |
6 | 1220054502105212104 |
7 | 41504255136010441 |
oct | 4005566340453750 |
9 | 614630585801674 |
10 | 141131342043112 |
11 | 40a7251432a103 |
12 | 139b4248a91034 |
13 | 60998229194c5 |
14 | 26bcb171462c8 |
15 | 114b23b80da77 |
hex | 805bb38257e8 |
141131342043112 has 16 divisors (see below), whose sum is σ = 264640552395300. Its totient is φ = 70560528071040.
The previous prime is 141131342043073. The next prime is 141131342043127. The reversal of 141131342043112 is 211340243131141.
141131342043112 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 133975856142436 + 7155485900676 = 11574794^2 + 2674974^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 642752187 + ... + 642971722.
Almost surely, 2141131342043112 is an apocalyptic number.
It is an amenable number.
141131342043112 is a deficient number, since it is larger than the sum of its proper divisors (123509210352188).
141131342043112 is a wasteful number, since it uses less digits than its factorization.
141131342043112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1285737636 (or 1285737632 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 141131342043112 its reverse (211340243131141), we get a palindrome (352471585174253).
The spelling of 141131342043112 in words is "one hundred forty-one trillion, one hundred thirty-one billion, three hundred forty-two million, forty-three thousand, one hundred twelve".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •