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141131400340241 is a prime number
BaseRepresentation
bin100000000101101110110110…
…111110111110001100010001
3200111201000210221120212101102
4200011232312332332030101
5121444244101441341431
61220054511550514145
741504256444353063
oct4005566676761421
9614630727525342
10141131400340241
1140a72544227653
12139b4264505955
136099831a1b34c
1426bcb20b9d733
15114b2419c6dcb
hex805bb6fbe311

141131400340241 has 2 divisors, whose sum is σ = 141131400340242. Its totient is φ = 141131400340240.

The previous prime is 141131400340159. The next prime is 141131400340303. The reversal of 141131400340241 is 142043004131141.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89713953345025 + 51417446995216 = 9471745^2 + 7170596^2 .

It is an emirp because it is prime and its reverse (142043004131141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141131400340241 - 214 = 141131400323857 is a prime.

It is not a weakly prime, because it can be changed into another prime (141131400346241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70565700170120 + 70565700170121.

It is an arithmetic number, because the mean of its divisors is an integer number (70565700170121).

Almost surely, 2141131400340241 is an apocalyptic number.

It is an amenable number.

141131400340241 is a deficient number, since it is larger than the sum of its proper divisors (1).

141131400340241 is an equidigital number, since it uses as much as digits as its factorization.

141131400340241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 141131400340241 its reverse (142043004131141), we get a palindrome (283174404471382).

The spelling of 141131400340241 in words is "one hundred forty-one trillion, one hundred thirty-one billion, four hundred million, three hundred forty thousand, two hundred forty-one".