141131441204311 has 4 divisors (see below), whose sum is σ = 141132039781824. Its totient is φ = 141130842626800.

The previous prime is 141131441204207. The next prime is 141131441204359. The reversal of 141131441204311 is 113402144131141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141131441204311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141131441214311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 298934950 + ... + 299406691.

It is an arithmetic number, because the mean of its divisors is an integer number (35283009945456).

Almost surely, 2^{141131441204311} is an apocalyptic number.

141131441204311 is a deficient number, since it is larger than the sum of its proper divisors (598577513).

141131441204311 is an equidigital number, since it uses as much as digits as its factorization.

141131441204311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 598577512.

The product of its (nonzero) digits is 4608, while the sum is 31.

Adding to 141131441204311 its reverse (113402144131141), we get a palindrome (254533585335452).

The spelling of 141131441204311 in words is "one hundred forty-one trillion, one hundred thirty-one billion, four hundred forty-one million, two hundred four thousand, three hundred eleven".