141132002114003 has 2 divisors, whose sum is σ = 141132002114004. Its totient is φ = 141132002114002.

The previous prime is 141132002113961. The next prime is 141132002114017. The reversal of 141132002114003 is 300411200231141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141132002114003 - 2¹⁸ = 141132001851859 is a prime.

It is a super-3 number, since 3×141132002114003³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 141132002114003.

It is not a weakly prime, because it can be changed into another prime (141132002114063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70566001057001 + 70566001057002.

It is an arithmetic number, because the mean of its divisors is an integer number (70566001057002).

Almost surely, 2^{141132002114003} is an apocalyptic number.

141132002114003 is a deficient number, since it is larger than the sum of its proper divisors (1).

141132002114003 is an equidigital number, since it uses as much as digits as its factorization.

141132002114003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 141132002114003 its reverse (300411200231141), we get a palindrome (441543202345144).

The spelling of 141132002114003 in words is "one hundred forty-one trillion, one hundred thirty-two billion, two million, one hundred fourteen thousand, three".