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141132041134 = 2710080860081
BaseRepresentation
bin1000001101110000100…
…0000000101110101110
3111111021201211112020121
42003130020000232232
54303014300304014
6144500221235154
713124245361530
oct2033410005656
9444251745217
10141132041134
11549433a3427
1223428a02aba
1310402280a16
146b8bb0b850
153a102d6124
hex20dc200bae

141132041134 has 8 divisors (see below), whose sum is σ = 241940641968. Its totient is φ = 60485160480.

The previous prime is 141132041111. The next prime is 141132041147. The reversal of 141132041134 is 431140231141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×1411320411343 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141132041099 and 141132041108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5040430027 + ... + 5040430054.

It is an arithmetic number, because the mean of its divisors is an integer number (30242580246).

Almost surely, 2141132041134 is an apocalyptic number.

141132041134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

141132041134 is a deficient number, since it is larger than the sum of its proper divisors (100808600834).

141132041134 is a wasteful number, since it uses less digits than its factorization.

141132041134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10080860090.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 141132041134 its reverse (431140231141), we get a palindrome (572272272275).

The spelling of 141132041134 in words is "one hundred forty-one billion, one hundred thirty-two million, forty-one thousand, one hundred thirty-four".

Divisors: 1 2 7 14 10080860081 20161720162 70566020567 141132041134