Base | Representation |
---|---|
bin | 100000000101101111011110… |
… | …011000100010110110101001 |
3 | 200111201002112000101220202120 |
4 | 200011233132120202312221 |
5 | 121444301430201333213 |
6 | 1220055101322421453 |
7 | 41504312022035061 |
oct | 4005573630426651 |
9 | 614632460356676 |
10 | 141132061355433 |
11 | 40a7285336a0a5 |
12 | 139b4409961889 |
13 | 609990895acb5 |
14 | 26bcb848aa3a1 |
15 | 114b27ea48423 |
hex | 805bde622da9 |
141132061355433 has 32 divisors (see below), whose sum is σ = 203138415067392. Its totient is φ = 86932872576000.
The previous prime is 141132061355339. The next prime is 141132061355477. The reversal of 141132061355433 is 334553160231141.
It is not a de Polignac number, because 141132061355433 - 210 = 141132061354409 is a prime.
It is a super-3 number, since 3×1411320613554333 (a number of 43 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (141132061355833) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 246682660 + ... + 247254117.
It is an arithmetic number, because the mean of its divisors is an integer number (6348075470856).
Almost surely, 2141132061355433 is an apocalyptic number.
It is an amenable number.
141132061355433 is a deficient number, since it is larger than the sum of its proper divisors (62006353711959).
141132061355433 is a wasteful number, since it uses less digits than its factorization.
141132061355433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 493936945.
The product of its (nonzero) digits is 388800, while the sum is 42.
The spelling of 141132061355433 in words is "one hundred forty-one trillion, one hundred thirty-two billion, sixty-one million, three hundred fifty-five thousand, four hundred thirty-three".
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