Base | Representation |
---|---|
bin | 100000000101101111100001… |
… | …011110000101110111101110 |
3 | 200111201002122121211220112001 |
4 | 200011233201132011313232 |
5 | 121444302031431004410 |
6 | 1220055110412402514 |
7 | 41504313221151061 |
oct | 4005574136056756 |
9 | 614632577756461 |
10 | 141132113141230 |
11 | 40a7287a61a582 |
12 | 139b442317643a |
13 | 60999165c0193 |
14 | 26bcb8b70a8d8 |
15 | 114b28437733a |
hex | 805be1785dee |
141132113141230 has 64 divisors (see below), whose sum is σ = 257899933203840. Its totient is φ = 55602391762944.
The previous prime is 141132113141203. The next prime is 141132113141237. The reversal of 141132113141230 is 32141311231141.
It is a super-3 number, since 3×1411321131412303 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141132113141237) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 114812506 + ... + 116035234.
It is an arithmetic number, because the mean of its divisors is an integer number (4029686456310).
Almost surely, 2141132113141230 is an apocalyptic number.
141132113141230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
141132113141230 is a deficient number, since it is larger than the sum of its proper divisors (116767820062610).
141132113141230 is a wasteful number, since it uses less digits than its factorization.
141132113141230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1223533.
The product of its (nonzero) digits is 1728, while the sum is 28.
Adding to 141132113141230 its reverse (32141311231141), we get a palindrome (173273424372371).
The spelling of 141132113141230 in words is "one hundred forty-one trillion, one hundred thirty-two billion, one hundred thirteen million, one hundred forty-one thousand, two hundred thirty".
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