Base | Representation |
---|---|
bin | 1100110101011111110011… |
… | …1111001111010011011001 |
3 | 1211222012200000021121122212 |
4 | 3031113330333033103121 |
5 | 3322212324233103140 |
6 | 50003304201124505 |
7 | 2654434356453614 |
oct | 315277477172331 |
9 | 54865600247585 |
10 | 14113212003545 |
11 | 455141a277586 |
12 | 16bb29a189735 |
13 | 7b4b40a33165 |
14 | 36b12408317b |
15 | 1971b4eb5765 |
hex | cd5fcfcf4d9 |
14113212003545 has 32 divisors (see below), whose sum is σ = 17984205584640. Its totient is φ = 10595537090560.
The previous prime is 14113212003481. The next prime is 14113212003551. The reversal of 14113212003545 is 54530021231141.
It is not a de Polignac number, because 14113212003545 - 26 = 14113212003481 is a prime.
It is a super-3 number, since 3×141132120035453 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 307903949 + ... + 307949781.
It is an arithmetic number, because the mean of its divisors is an integer number (562006424520).
Almost surely, 214113212003545 is an apocalyptic number.
It is an amenable number.
14113212003545 is a deficient number, since it is larger than the sum of its proper divisors (3870993581095).
14113212003545 is a wasteful number, since it uses less digits than its factorization.
14113212003545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56305.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 14113212003545 its reverse (54530021231141), we get a palindrome (68643233234686).
The spelling of 14113212003545 in words is "fourteen trillion, one hundred thirteen billion, two hundred twelve million, three thousand, five hundred forty-five".
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