141132202021211 has 4 divisors (see below), whose sum is σ = 143065519857192. Its totient is φ = 139198884185232.

The previous prime is 141132202021199. The next prime is 141132202021219. The reversal of 141132202021211 is 112120202231141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141132202021211 - 2³⁰ = 141131128279387 is a prime.

It is a super-3 number, since 3×141132202021211³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141132202021219) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 966658917881 + ... + 966658918026.

It is an arithmetic number, because the mean of its divisors is an integer number (35766379964298).

Almost surely, 2^{141132202021211} is an apocalyptic number.

141132202021211 is a deficient number, since it is larger than the sum of its proper divisors (1933317835981).

141132202021211 is an equidigital number, since it uses as much as digits as its factorization.

141132202021211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1933317835980.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 141132202021211 its reverse (112120202231141), we get a palindrome (253252404252352).

The spelling of 141132202021211 in words is "one hundred forty-one trillion, one hundred thirty-two billion, two hundred two million, twenty-one thousand, two hundred eleven".