141132232122113 has 4 divisors (see below), whose sum is σ = 144946616774100. Its totient is φ = 137317847470128.

The previous prime is 141132232122103. The next prime is 141132232122121. The reversal of 141132232122113 is 311221232231141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 82885601847409 + 58246630274704 = 9104153^2 + 7631948^2 .

It is a cyclic number.

It is not a de Polignac number, because 141132232122113 - 2²⁸ = 141131963686657 is a prime.

It is a super-3 number, since 3×141132232122113³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (141132232122103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1907192325938 + ... + 1907192326011.

It is an arithmetic number, because the mean of its divisors is an integer number (36236654193525).

Almost surely, 2^{141132232122113} is an apocalyptic number.

It is an amenable number.

141132232122113 is a deficient number, since it is larger than the sum of its proper divisors (3814384651987).

141132232122113 is an equidigital number, since it uses as much as digits as its factorization.

141132232122113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3814384651986.

The product of its digits is 3456, while the sum is 29.

Adding to 141132232122113 its reverse (311221232231141), we get a palindrome (452353464353254).

The spelling of 141132232122113 in words is "one hundred forty-one trillion, one hundred thirty-two billion, two hundred thirty-two million, one hundred twenty-two thousand, one hundred thirteen".