Base | Representation |
---|---|
bin | 1000001101110000100… |
… | …0110100001111110001 |
3 | 111111021202020020200211 |
4 | 2003130020310033301 |
5 | 4303014324032040 |
6 | 144500225544121 |
7 | 13124250230653 |
oct | 2033410641761 |
9 | 444252206624 |
10 | 141132252145 |
11 | 54943527a15 |
12 | 23428aa5041 |
13 | 10402325a91 |
14 | 6b8bb646d3 |
15 | 3a103288ea |
hex | 20dc2343f1 |
141132252145 has 32 divisors (see below), whose sum is σ = 186176102400. Its totient is φ = 102241643520.
The previous prime is 141132252101. The next prime is 141132252161. The reversal of 141132252145 is 541252231141.
It is not a de Polignac number, because 141132252145 - 213 = 141132243953 is a prime.
It is a super-3 number, since 3×1411322521453 (a number of 34 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 301056 + ... + 610654.
It is an arithmetic number, because the mean of its divisors is an integer number (5818003200).
Almost surely, 2141132252145 is an apocalyptic number.
It is an amenable number.
141132252145 is a deficient number, since it is larger than the sum of its proper divisors (45043850255).
141132252145 is a wasteful number, since it uses less digits than its factorization.
141132252145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 309825.
The product of its digits is 9600, while the sum is 31.
Adding to 141132252145 its reverse (541252231141), we get a palindrome (682384483286).
The spelling of 141132252145 in words is "one hundred forty-one billion, one hundred thirty-two million, two hundred fifty-two thousand, one hundred forty-five".
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