Base | Representation |
---|---|
bin | 1100110101011111111001… |
… | …0000111111010111111110 |
3 | 1211222012201111121101212111 |
4 | 3031113332100333113332 |
5 | 3322212400224342420 |
6 | 50003310244324234 |
7 | 2654435036561446 |
oct | 315277620772776 |
9 | 54865644541774 |
10 | 14113233434110 |
11 | 4551430384698 |
12 | 16bb2a53a367a |
13 | 7b4b452c7775 |
14 | 36b126c61126 |
15 | 1971b6cea45a |
hex | cd5fe43f5fe |
14113233434110 has 32 divisors (see below), whose sum is σ = 27393079543200. Its totient is φ = 5217729431040.
The previous prime is 14113233434101. The next prime is 14113233434141. The reversal of 14113233434110 is 1143433231141.
It is a super-3 number, since 3×141132334341103 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 905848015 + ... + 905863594.
It is an arithmetic number, because the mean of its divisors is an integer number (856033735725).
Almost surely, 214113233434110 is an apocalyptic number.
14113233434110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14113233434110 is a deficient number, since it is larger than the sum of its proper divisors (13279846109090).
14113233434110 is a wasteful number, since it uses less digits than its factorization.
14113233434110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1811711676.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 14113233434110 its reverse (1143433231141), we get a palindrome (15256666665251).
The spelling of 14113233434110 in words is "fourteen trillion, one hundred thirteen billion, two hundred thirty-three million, four hundred thirty-four thousand, one hundred ten".
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