141132341102122 has 4 divisors (see below), whose sum is σ = 211698511653186. Its totient is φ = 70566170551060.

The previous prime is 141132341102099. The next prime is 141132341102131. The reversal of 141132341102122 is 221201143231141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 81212340980521 + 59920000121601 = 9011789^2 + 7740801^2 .

It is a super-3 number, since 3×141132341102122³ (a number of 43 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35283085275529 + ... + 35283085275532.

Almost surely, 2^{141132341102122} is an apocalyptic number.

141132341102122 is a deficient number, since it is larger than the sum of its proper divisors (70566170551064).

141132341102122 is an equidigital number, since it uses as much as digits as its factorization.

141132341102122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70566170551063.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 141132341102122 its reverse (221201143231141), we get a palindrome (362333484333263).

The spelling of 141132341102122 in words is "one hundred forty-one trillion, one hundred thirty-two billion, three hundred forty-one million, one hundred two thousand, one hundred twenty-two".