Base | Representation |
---|---|
bin | 100000000101101111110011… |
… | …001010101011100010010011 |
3 | 200111201010102022112001111221 |
4 | 200011233303022223202103 |
5 | 121444303133432330030 |
6 | 1220055200100145511 |
7 | 41504323454603353 |
oct | 4005576312534223 |
9 | 614633368461457 |
10 | 141132410042515 |
11 | 40a72a12177941 |
12 | 139b44a6698297 |
13 | 6099962c74708 |
14 | 26bcbb8d14b63 |
15 | 114b2a0472e7a |
hex | 805bf32ab893 |
141132410042515 has 32 divisors (see below), whose sum is σ = 178422376204800. Its totient is φ = 106873606932480.
The previous prime is 141132410042461. The next prime is 141132410042549. The reversal of 141132410042515 is 515240014231141.
It is not a de Polignac number, because 141132410042515 - 219 = 141132409518227 is a prime.
It is a super-3 number, since 3×1411324100425153 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2566809714 + ... + 2566864696.
It is an arithmetic number, because the mean of its divisors is an integer number (5575699256400).
Almost surely, 2141132410042515 is an apocalyptic number.
141132410042515 is a deficient number, since it is larger than the sum of its proper divisors (37289966162285).
141132410042515 is a wasteful number, since it uses less digits than its factorization.
141132410042515 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 77227.
The product of its (nonzero) digits is 19200, while the sum is 34.
Adding to 141132410042515 its reverse (515240014231141), we get a palindrome (656372424273656).
The spelling of 141132410042515 in words is "one hundred forty-one trillion, one hundred thirty-two billion, four hundred ten million, forty-two thousand, five hundred fifteen".
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