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1411324132213 is a prime number
BaseRepresentation
bin10100100010011001011…
…110010011101101110101
311222220212121100022112001
4110202121132103231311
5141110342434212323
63000204154055301
7203651633121532
oct24423136235565
94886777308461
101411324132213
114a45a2752446
121a963571a531
13a3119a2b518
144c446571d89
1526aa23c83ad
hex14899793b75

1411324132213 has 2 divisors, whose sum is σ = 1411324132214. Its totient is φ = 1411324132212.

The previous prime is 1411324132151. The next prime is 1411324132237. The reversal of 1411324132213 is 3122314231141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 954183173329 + 457140958884 = 976823^2 + 676122^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1411324132213 is a prime.

It is a super-3 number, since 3×14113241322133 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1411324132313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705662066106 + 705662066107.

It is an arithmetic number, because the mean of its divisors is an integer number (705662066107).

Almost surely, 21411324132213 is an apocalyptic number.

It is an amenable number.

1411324132213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411324132213 is an equidigital number, since it uses as much as digits as its factorization.

1411324132213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3456, while the sum is 28.

Adding to 1411324132213 its reverse (3122314231141), we get a palindrome (4533638363354).

The spelling of 1411324132213 in words is "one trillion, four hundred eleven billion, three hundred twenty-four million, one hundred thirty-two thousand, two hundred thirteen".