Base | Representation |
---|---|
bin | 11010010010011011… |
… | …10010001011001001 |
3 | 1100102120120111011120 |
4 | 31021031302023021 |
5 | 212400443031131 |
6 | 10252235545453 |
7 | 1006511443260 |
oct | 151115621311 |
9 | 40376514146 |
10 | 14113252041 |
11 | 5a92621169 |
12 | 289a5bb289 |
13 | 143bc12515 |
14 | 97c5575d7 |
15 | 579054496 |
hex | 3493722c9 |
14113252041 has 24 divisors (see below), whose sum is σ = 22697383104. Its totient is φ = 7640252640.
The previous prime is 14113252033. The next prime is 14113252057. The reversal of 14113252041 is 14025231141.
It is not a de Polignac number, because 14113252041 - 23 = 14113252033 is a prime.
It is a super-3 number, since 3×141132520413 (a number of 31 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (14113252141) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 923250 + ... + 938411.
It is an arithmetic number, because the mean of its divisors is an integer number (945724296).
Almost surely, 214113252041 is an apocalyptic number.
It is an amenable number.
14113252041 is a deficient number, since it is larger than the sum of its proper divisors (8584131063).
14113252041 is a wasteful number, since it uses less digits than its factorization.
14113252041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1861709 (or 1861690 counting only the distinct ones).
The product of its (nonzero) digits is 960, while the sum is 24.
Adding to 14113252041 its reverse (14025231141), we get a palindrome (28138483182).
The spelling of 14113252041 in words is "fourteen billion, one hundred thirteen million, two hundred fifty-two thousand, forty-one".
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