Base | Representation |
---|---|
bin | 1000001101110000101… |
… | …1110010111010101100 |
3 | 111111021210200221000021 |
4 | 2003130023302322230 |
5 | 4303020024030012 |
6 | 144500254411524 |
7 | 13124256662620 |
oct | 2033413627254 |
9 | 444253627007 |
10 | 141133033132 |
11 | 54943a10763 |
12 | 23429200ba4 |
13 | 1040253a3c0 |
14 | 6b8bcc9180 |
15 | 3a10430007 |
hex | 20dc2f2eac |
141133033132 has 48 divisors (see below), whose sum is σ = 304656206400. Its totient is φ = 55708434432.
The previous prime is 141133033117. The next prime is 141133033229. The reversal of 141133033132 is 231330331141.
141133033132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 141133033097 and 141133033106.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 268333 + ... + 595204.
It is an arithmetic number, because the mean of its divisors is an integer number (6347004300).
Almost surely, 2141133033132 is an apocalyptic number.
It is an amenable number.
141133033132 is an abundant number, since it is smaller than the sum of its proper divisors (163523173268).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141133033132 is a wasteful number, since it uses less digits than its factorization.
141133033132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 864010 (or 864008 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 141133033132 its reverse (231330331141), we get a palindrome (372463364273).
The spelling of 141133033132 in words is "one hundred forty-one billion, one hundred thirty-three million, thirty-three thousand, one hundred thirty-two".
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