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14113333113 = 311427676761
BaseRepresentation
bin11010010010011100…
…00101111101111001
31100102120201121101020
431021032011331321
5212401003124423
610252241413053
71006512231525
oct151116057571
940376647336
1014113333113
115a92677070
12289a63a189
13143bc403a9
1497c578d85
1557906d4e3
hex349385f79

14113333113 has 8 divisors (see below), whose sum is σ = 20528484576. Its totient is φ = 8553535200.

The previous prime is 14113333099. The next prime is 14113333147. The reversal of 14113333113 is 31133331141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14113333113 - 213 = 14113324921 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14113333313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 213838348 + ... + 213838413.

It is an arithmetic number, because the mean of its divisors is an integer number (2566060572).

Almost surely, 214113333113 is an apocalyptic number.

It is an amenable number.

14113333113 is a deficient number, since it is larger than the sum of its proper divisors (6415151463).

14113333113 is a wasteful number, since it uses less digits than its factorization.

14113333113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 427676775.

The product of its digits is 972, while the sum is 24.

Adding to 14113333113 its reverse (31133331141), we get a palindrome (45246664254).

It can be divided in two parts, 1 and 4113333113, that added together give a palindrome (4113333114).

The spelling of 14113333113 in words is "fourteen billion, one hundred thirteen million, three hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 3 11 33 427676761 1283030283 4704444371 14113333113