Base | Representation |
---|---|
bin | 11010010010011100… |
… | …01000011000011011 |
3 | 1100102120202002221112 |
4 | 31021032020120123 |
5 | 212401003434003 |
6 | 10252241530535 |
7 | 1006512302414 |
oct | 151116103033 |
9 | 40376662845 |
10 | 14113343003 |
11 | 5a92683541 |
12 | 289a643a4b |
13 | 143bc44a46 |
14 | 97c57c80b |
15 | 5790713d8 |
hex | 34938861b |
14113343003 has 2 divisors, whose sum is σ = 14113343004. Its totient is φ = 14113343002.
The previous prime is 14113342993. The next prime is 14113343059. The reversal of 14113343003 is 30034331141.
It is a weak prime.
It is an emirp because it is prime and its reverse (30034331141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14113343003 - 24 = 14113342987 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14113343003.
It is not a weakly prime, because it can be changed into another prime (14113343063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056671501 + 7056671502.
It is an arithmetic number, because the mean of its divisors is an integer number (7056671502).
Almost surely, 214113343003 is an apocalyptic number.
14113343003 is a deficient number, since it is larger than the sum of its proper divisors (1).
14113343003 is an equidigital number, since it uses as much as digits as its factorization.
14113343003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 14113343003 its reverse (30034331141), we get a palindrome (44147674144).
The spelling of 14113343003 in words is "fourteen billion, one hundred thirteen million, three hundred forty-three thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •