14113343131 has 2 divisors, whose sum is σ = 14113343132. Its totient is φ = 14113343130.

The previous prime is 14113343119. The next prime is 14113343137. The reversal of 14113343131 is 13134331141.

It is a strong prime.

It is an emirp because it is prime and its reverse (13134331141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14113343131 - 2⁷ = 14113343003 is a prime.

It is a super-2 number, since 2×14113343131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14113343096 and 14113343105.

It is not a weakly prime, because it can be changed into another prime (14113343137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056671565 + 7056671566.

It is an arithmetic number, because the mean of its divisors is an integer number (7056671566).

Almost surely, 2^14113343131 is an apocalyptic number.

14113343131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14113343131 is an equidigital number, since it uses as much as digits as its factorization.

14113343131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1296, while the sum is 25.

Adding to 14113343131 its reverse (13134331141), we get a palindrome (27247674272).

The spelling of 14113343131 in words is "fourteen billion, one hundred thirteen million, three hundred forty-three thousand, one hundred thirty-one".