14113343323 has 8 divisors (see below), whose sum is σ = 14290023888. Its totient is φ = 13936821024.

The previous prime is 14113343303. The next prime is 14113343333. The reversal of 14113343323 is 32334331141.

14113343323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14113343323 - 2²⁹ = 13576472411 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14113343291 and 14113343300.

It is not an unprimeable number, because it can be changed into a prime (14113343303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 145261 + ... + 222097.

It is an arithmetic number, because the mean of its divisors is an integer number (1786252986).

Almost surely, 2^14113343323 is an apocalyptic number.

14113343323 is a deficient number, since it is larger than the sum of its proper divisors (176680565).

14113343323 is an equidigital number, since it uses as much as digits as its factorization.

14113343323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79133.

The product of its digits is 7776, while the sum is 28.

Adding to 14113343323 its reverse (32334331141), we get a palindrome (46447674464).

The spelling of 14113343323 in words is "fourteen billion, one hundred thirteen million, three hundred forty-three thousand, three hundred twenty-three".