Base | Representation |
---|---|
bin | 101010000011111… |
… | …0101011011100011 |
3 | 10122100200111111222 |
4 | 1110013311123203 |
5 | 10342300340003 |
6 | 352013525255 |
7 | 46655122613 |
oct | 12407653343 |
9 | 3570614458 |
10 | 1411340003 |
11 | 6647346a7 |
12 | 3347a382b |
13 | 19651c238 |
14 | d5624a43 |
15 | 83d84c38 |
hex | 541f56e3 |
1411340003 has 4 divisors (see below), whose sum is σ = 1435261080. Its totient is φ = 1387418928.
The previous prime is 1411339997. The next prime is 1411340033. The reversal of 1411340003 is 3000431141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1411340003 - 28 = 1411339747 is a prime.
It is a super-3 number, since 3×14113400033 (a number of 28 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1411340033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11960450 + ... + 11960567.
It is an arithmetic number, because the mean of its divisors is an integer number (358815270).
Almost surely, 21411340003 is an apocalyptic number.
1411340003 is a deficient number, since it is larger than the sum of its proper divisors (23921077).
1411340003 is an equidigital number, since it uses as much as digits as its factorization.
1411340003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23921076.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 1411340003 is about 37567.8054056928. The cubic root of 1411340003 is about 1121.7012842790.
Adding to 1411340003 its reverse (3000431141), we get a palindrome (4411771144).
The spelling of 1411340003 in words is "one billion, four hundred eleven million, three hundred forty thousand, three".
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