Base | Representation |
---|---|
bin | 1100110101100000100100… |
… | …0001110011001000110001 |
3 | 1211222020012002101011100112 |
4 | 3031120021001303020301 |
5 | 3322213232441014301 |
6 | 50003340214431105 |
7 | 2654442361431224 |
oct | 315301101631061 |
9 | 54866162334315 |
10 | 14113414001201 |
11 | 45515132a4399 |
12 | 16bb335962495 |
13 | 7b4b738397b8 |
14 | 36b142c255bb |
15 | 1971c7ab69bb |
hex | cd609073231 |
14113414001201 has 2 divisors, whose sum is σ = 14113414001202. Its totient is φ = 14113414001200.
The previous prime is 14113414001177. The next prime is 14113414001243. The reversal of 14113414001201 is 10210041431141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11662388920576 + 2451025080625 = 3415024^2 + 1565575^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14113414001201 is a prime.
It is not a weakly prime, because it can be changed into another prime (14113414001801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056707000600 + 7056707000601.
It is an arithmetic number, because the mean of its divisors is an integer number (7056707000601).
Almost surely, 214113414001201 is an apocalyptic number.
It is an amenable number.
14113414001201 is a deficient number, since it is larger than the sum of its proper divisors (1).
14113414001201 is an equidigital number, since it uses as much as digits as its factorization.
14113414001201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 14113414001201 its reverse (10210041431141), we get a palindrome (24323455432342).
The spelling of 14113414001201 in words is "fourteen trillion, one hundred thirteen billion, four hundred fourteen million, one thousand, two hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •