Base | Representation |
---|---|
bin | 11010010010011101… |
… | …00000111001001011 |
3 | 1100102120221012200001 |
4 | 31021032200321023 |
5 | 212401020142103 |
6 | 10252244023431 |
7 | 1006513201213 |
oct | 151116407113 |
9 | 40376835601 |
10 | 14113443403 |
11 | 5a92741a14 |
12 | 289a691b77 |
13 | 143bc7b657 |
14 | 97c5a7243 |
15 | 57909101d |
hex | 3493a0e4b |
14113443403 has 8 divisors (see below), whose sum is σ = 14525844480. Its totient is φ = 13706976360.
The previous prime is 14113443397. The next prime is 14113443413. The reversal of 14113443403 is 30434431141.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14113443403 - 213 = 14113435211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14113443413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1478683 + ... + 1488196.
It is an arithmetic number, because the mean of its divisors is an integer number (1815730560).
Almost surely, 214113443403 is an apocalyptic number.
14113443403 is a deficient number, since it is larger than the sum of its proper divisors (412401077).
14113443403 is an equidigital number, since it uses as much as digits as its factorization.
14113443403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2967017.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 14113443403 its reverse (30434431141), we get a palindrome (44547874544).
The spelling of 14113443403 in words is "fourteen billion, one hundred thirteen million, four hundred forty-three thousand, four hundred three".
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