14113444432141 has 2 divisors, whose sum is σ = 14113444432142. Its totient is φ = 14113444432140.

The previous prime is 14113444432133. The next prime is 14113444432183. The reversal of 14113444432141 is 14123444431141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12203990283241 + 1909454148900 = 3493421^2 + 1381830^2 .

It is an emirp because it is prime and its reverse (14123444431141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14113444432141 - 2³ = 14113444432133 is a prime.

It is a super-3 number, since 3×14113444432141³ (a number of 40 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14113444432141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14113444433141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056722216070 + 7056722216071.

It is an arithmetic number, because the mean of its divisors is an integer number (7056722216071).

Almost surely, 2^{14113444432141} is an apocalyptic number.

It is an amenable number.

14113444432141 is a deficient number, since it is larger than the sum of its proper divisors (1).

14113444432141 is an equidigital number, since it uses as much as digits as its factorization.

14113444432141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 73728, while the sum is 37.

Adding to 14113444432141 its reverse (14123444431141), we get a palindrome (28236888863282).

It can be divided in two parts, 1411344 and 4432141, that added together give a palindrome (5843485).

The spelling of 14113444432141 in words is "fourteen trillion, one hundred thirteen billion, four hundred forty-four million, four hundred thirty-two thousand, one hundred forty-one".