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141135400453 is a prime number
BaseRepresentation
bin1000001101110001010…
…0110100111000000101
3111111021222011012100211
42003130110310320011
54303021130303303
6144500421235421
713124316052465
oct2033424647005
9444258135324
10141135400453
1154945288323
1223429b62b71
1310402b88a98
146b8c343ba5
153a1074b66d
hex20dc534e05

141135400453 has 2 divisors, whose sum is σ = 141135400454. Its totient is φ = 141135400452.

The previous prime is 141135400421. The next prime is 141135400459. The reversal of 141135400453 is 354004531141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126382383009 + 14753017444 = 355503^2 + 121462^2 .

It is a cyclic number.

It is not a de Polignac number, because 141135400453 - 25 = 141135400421 is a prime.

It is a super-2 number, since 2×1411354004532 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141135400459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70567700226 + 70567700227.

It is an arithmetic number, because the mean of its divisors is an integer number (70567700227).

Almost surely, 2141135400453 is an apocalyptic number.

It is an amenable number.

141135400453 is a deficient number, since it is larger than the sum of its proper divisors (1).

141135400453 is an equidigital number, since it uses as much as digits as its factorization.

141135400453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 141135400453 its reverse (354004531141), we get a palindrome (495139931594).

The spelling of 141135400453 in words is "one hundred forty-one billion, one hundred thirty-five million, four hundred thousand, four hundred fifty-three".