Base | Representation |
---|---|
bin | 1000001101110001010… |
… | …0110100111000000101 |
3 | 111111021222011012100211 |
4 | 2003130110310320011 |
5 | 4303021130303303 |
6 | 144500421235421 |
7 | 13124316052465 |
oct | 2033424647005 |
9 | 444258135324 |
10 | 141135400453 |
11 | 54945288323 |
12 | 23429b62b71 |
13 | 10402b88a98 |
14 | 6b8c343ba5 |
15 | 3a1074b66d |
hex | 20dc534e05 |
141135400453 has 2 divisors, whose sum is σ = 141135400454. Its totient is φ = 141135400452.
The previous prime is 141135400421. The next prime is 141135400459. The reversal of 141135400453 is 354004531141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 126382383009 + 14753017444 = 355503^2 + 121462^2 .
It is a cyclic number.
It is not a de Polignac number, because 141135400453 - 25 = 141135400421 is a prime.
It is a super-2 number, since 2×1411354004532 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141135400459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70567700226 + 70567700227.
It is an arithmetic number, because the mean of its divisors is an integer number (70567700227).
Almost surely, 2141135400453 is an apocalyptic number.
It is an amenable number.
141135400453 is a deficient number, since it is larger than the sum of its proper divisors (1).
141135400453 is an equidigital number, since it uses as much as digits as its factorization.
141135400453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 141135400453 its reverse (354004531141), we get a palindrome (495139931594).
The spelling of 141135400453 in words is "one hundred forty-one billion, one hundred thirty-five million, four hundred thousand, four hundred fifty-three".
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