14113550042133 has 4 divisors (see below), whose sum is σ = 18818066722848. Its totient is φ = 9409033361420.

The previous prime is 14113550042117. The next prime is 14113550042171. The reversal of 14113550042133 is 33124005531141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14113550042133 - 2⁴ = 14113550042117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14113550042094 and 14113550042103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14113570042133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2352258340353 + ... + 2352258340358.

It is an arithmetic number, because the mean of its divisors is an integer number (4704516680712).

Almost surely, 2^{14113550042133} is an apocalyptic number.

It is an amenable number.

14113550042133 is a deficient number, since it is larger than the sum of its proper divisors (4704516680715).

14113550042133 is an equidigital number, since it uses as much as digits as its factorization.

14113550042133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4704516680714.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 14113550042133 its reverse (33124005531141), we get a palindrome (47237555573274).

The spelling of 14113550042133 in words is "fourteen trillion, one hundred thirteen billion, five hundred fifty million, forty-two thousand, one hundred thirty-three".