1411381525471 has 4 divisors (see below), whose sum is σ = 1425084258832. Its totient is φ = 1397678792112.

The previous prime is 1411381525469. The next prime is 1411381525483. The reversal of 1411381525471 is 1745251831141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1411381525471 - 2¹ = 1411381525469 is a prime.

It is a super-3 number, since 3×1411381525471³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1411381525451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6851366526 + ... + 6851366731.

It is an arithmetic number, because the mean of its divisors is an integer number (356271064708).

Almost surely, 2^{1411381525471} is an apocalyptic number.

1411381525471 is a deficient number, since it is larger than the sum of its proper divisors (13702733361).

1411381525471 is a wasteful number, since it uses less digits than its factorization.

1411381525471 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13702733360.

The product of its digits is 134400, while the sum is 43.

The spelling of 1411381525471 in words is "one trillion, four hundred eleven billion, three hundred eighty-one million, five hundred twenty-five thousand, four hundred seventy-one".