Base | Representation |
---|---|
bin | 100000000101110111010000… |
… | …000111110001011100000101 |
3 | 200111201220001222122020102222 |
4 | 200011313100013301130011 |
5 | 121444421030433343133 |
6 | 1220103002110142125 |
7 | 41505025661326331 |
oct | 4005672007613405 |
9 | 614656058566388 |
10 | 141140412012293 |
11 | 40a76349070201 |
12 | 139b5b5a4b1945 |
13 | 609a639a27285 |
14 | 26bd3379727c1 |
15 | 114b5bcc0be98 |
hex | 805dd01f1705 |
141140412012293 has 2 divisors, whose sum is σ = 141140412012294. Its totient is φ = 141140412012292.
The previous prime is 141140412012227. The next prime is 141140412012317. The reversal of 141140412012293 is 392210214041141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 94761015913729 + 46379396098564 = 9734527^2 + 6810242^2 .
It is a cyclic number.
It is not a de Polignac number, because 141140412012293 - 28 = 141140412012037 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141140412012793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70570206006146 + 70570206006147.
It is an arithmetic number, because the mean of its divisors is an integer number (70570206006147).
Almost surely, 2141140412012293 is an apocalyptic number.
It is an amenable number.
141140412012293 is a deficient number, since it is larger than the sum of its proper divisors (1).
141140412012293 is an equidigital number, since it uses as much as digits as its factorization.
141140412012293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 35.
The spelling of 141140412012293 in words is "one hundred forty-one trillion, one hundred forty billion, four hundred twelve million, twelve thousand, two hundred ninety-three".
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