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141141300151 = 405134841101
BaseRepresentation
bin1000001101110010101…
…1010101001110110111
3111111022101020221020011
42003130223111032313
54303024133101101
6144501151521051
713124420153665
oct2033453251667
9444271227204
10141141300151
1154948647905
122342bb29187
1310404173227
146b8d03bc35
153a11014751
hex20dcad53b7

141141300151 has 4 divisors (see below), whose sum is σ = 141176145304. Its totient is φ = 141106455000.

The previous prime is 141141300133. The next prime is 141141300163. The reversal of 141141300151 is 151003141141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 151003141141 = 626872408843.

It is a cyclic number.

It is not a de Polignac number, because 141141300151 - 25 = 141141300119 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141141300451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17416500 + ... + 17424601.

It is an arithmetic number, because the mean of its divisors is an integer number (35294036326).

Almost surely, 2141141300151 is an apocalyptic number.

141141300151 is a deficient number, since it is larger than the sum of its proper divisors (34845153).

141141300151 is an equidigital number, since it uses as much as digits as its factorization.

141141300151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34845152.

The product of its (nonzero) digits is 240, while the sum is 22.

Adding to 141141300151 its reverse (151003141141), we get a palindrome (292144441292).

The spelling of 141141300151 in words is "one hundred forty-one billion, one hundred forty-one million, three hundred thousand, one hundred fifty-one".

Divisors: 1 4051 34841101 141141300151