Base | Representation |
---|---|
bin | 10100100010011111010… |
… | …100001000000100000111 |
3 | 11222221010102201221012021 |
4 | 110202133110020010013 |
5 | 141111043031020333 |
6 | 3000222014304011 |
7 | 203654233060645 |
oct | 24423724100407 |
9 | 4887112657167 |
10 | 1411422126343 |
11 | 4a4642aa3929 |
12 | 1a96624b8007 |
13 | a313411c008 |
14 | 4c4555a0195 |
15 | 26aaacd382d |
hex | 1489f508107 |
1411422126343 has 2 divisors, whose sum is σ = 1411422126344. Its totient is φ = 1411422126342.
The previous prime is 1411422126307. The next prime is 1411422126347. The reversal of 1411422126343 is 3436212241141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1411422126343 - 225 = 1411388571911 is a prime.
It is a super-2 number, since 2×14114221263432 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1411422126299 and 1411422126308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1411422126347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705711063171 + 705711063172.
It is an arithmetic number, because the mean of its divisors is an integer number (705711063172).
Almost surely, 21411422126343 is an apocalyptic number.
1411422126343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1411422126343 is an equidigital number, since it uses as much as digits as its factorization.
1411422126343 is an evil number, because the sum of its binary digits is even.
The product of its digits is 27648, while the sum is 34.
Adding to 1411422126343 its reverse (3436212241141), we get a palindrome (4847634367484).
The spelling of 1411422126343 in words is "one trillion, four hundred eleven billion, four hundred twenty-two million, one hundred twenty-six thousand, three hundred forty-three".
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