Base | Representation |
---|---|
bin | 11010010010100011… |
… | …00001001111010011 |
3 | 1100102122102020101121 |
4 | 31021101201033103 |
5 | 212401220400001 |
6 | 10252312543111 |
7 | 1006522662151 |
oct | 151121411723 |
9 | 40378366347 |
10 | 14114231251 |
11 | 5a9312a92a |
12 | 289a9b1a97 |
13 | 143c196133 |
14 | 97c7303d1 |
15 | 5791996a1 |
hex | 3494613d3 |
14114231251 has 2 divisors, whose sum is σ = 14114231252. Its totient is φ = 14114231250.
The previous prime is 14114231237. The next prime is 14114231293. The reversal of 14114231251 is 15213241141.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14114231251 - 213 = 14114223059 is a prime.
It is not a weakly prime, because it can be changed into another prime (14114231051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057115625 + 7057115626.
It is an arithmetic number, because the mean of its divisors is an integer number (7057115626).
Almost surely, 214114231251 is an apocalyptic number.
14114231251 is a deficient number, since it is larger than the sum of its proper divisors (1).
14114231251 is an equidigital number, since it uses as much as digits as its factorization.
14114231251 is an evil number, because the sum of its binary digits is even.
The product of its digits is 960, while the sum is 25.
Adding to 14114231251 its reverse (15213241141), we get a palindrome (29327472392).
The spelling of 14114231251 in words is "fourteen billion, one hundred fourteen million, two hundred thirty-one thousand, two hundred fifty-one".
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