Base | Representation |
---|---|
bin | 10100100010100000100… |
… | …100111110100110011011 |
3 | 11222221011220121202010120 |
4 | 110202200210332212123 |
5 | 141111113442234433 |
6 | 3000224052444323 |
7 | 203654611164444 |
oct | 24424044764633 |
9 | 4887156552116 |
10 | 1411443321243 |
11 | 4a4653a5a97a |
12 | 1a96696196a3 |
13 | a3138630287 |
14 | 4c45831a2cb |
15 | 26aacabd7b3 |
hex | 148a093e99b |
1411443321243 has 4 divisors (see below), whose sum is σ = 1881924428328. Its totient is φ = 940962214160.
The previous prime is 1411443321221. The next prime is 1411443321307. The reversal of 1411443321243 is 3421233441141.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1411443321243 - 222 = 1411439126939 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1411443321203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235240553538 + ... + 235240553543.
It is an arithmetic number, because the mean of its divisors is an integer number (470481107082).
Almost surely, 21411443321243 is an apocalyptic number.
1411443321243 is a deficient number, since it is larger than the sum of its proper divisors (470481107085).
1411443321243 is an equidigital number, since it uses as much as digits as its factorization.
1411443321243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 470481107084.
The product of its digits is 27648, while the sum is 33.
Adding to 1411443321243 its reverse (3421233441141), we get a palindrome (4832676762384).
The spelling of 1411443321243 in words is "one trillion, four hundred eleven billion, four hundred forty-three million, three hundred twenty-one thousand, two hundred forty-three".
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