Base | Representation |
---|---|
bin | 1100110101100100101000… |
… | …0001100010110010110011 |
3 | 1211222100000002020212102021 |
4 | 3031121022001202302303 |
5 | 3322223001120001144 |
6 | 50004040330532311 |
7 | 2654511402216655 |
oct | 315311201426263 |
9 | 54870002225367 |
10 | 14114504453299 |
11 | 4551a22888178 |
12 | 16bb59ab97097 |
13 | 7b4cb8726623 |
14 | 36b20799a6d5 |
15 | 19723d6b3884 |
hex | cd64a062cb3 |
14114504453299 has 2 divisors, whose sum is σ = 14114504453300. Its totient is φ = 14114504453298.
The previous prime is 14114504453281. The next prime is 14114504453351. The reversal of 14114504453299 is 99235440541141.
It is an a-pointer prime, because the next prime (14114504453351) can be obtained adding 14114504453299 to its sum of digits (52).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14114504453299 - 25 = 14114504453267 is a prime.
It is not a weakly prime, because it can be changed into another prime (14114504453899) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057252226649 + 7057252226650.
It is an arithmetic number, because the mean of its divisors is an integer number (7057252226650).
Almost surely, 214114504453299 is an apocalyptic number.
14114504453299 is a deficient number, since it is larger than the sum of its proper divisors (1).
14114504453299 is an equidigital number, since it uses as much as digits as its factorization.
14114504453299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3110400, while the sum is 52.
The spelling of 14114504453299 in words is "fourteen trillion, one hundred fourteen billion, five hundred four million, four hundred fifty-three thousand, two hundred ninety-nine".
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