Base | Representation |
---|---|
bin | 1000001101110011111… |
… | …1001100100011001111 |
3 | 111111022202001111022212 |
4 | 2003130333030203033 |
5 | 4303032001214341 |
6 | 144501455301035 |
7 | 13124512342454 |
oct | 2033477144317 |
9 | 444282044285 |
10 | 141146507471 |
11 | 54950584182 |
12 | 2343181a77b |
13 | 10405277498 |
14 | 6b8d9d582b |
15 | 3a116e25eb |
hex | 20dcfcc8cf |
141146507471 has 2 divisors, whose sum is σ = 141146507472. Its totient is φ = 141146507470.
The previous prime is 141146507459. The next prime is 141146507561. The reversal of 141146507471 is 174705641141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141146507471 - 26 = 141146507407 is a prime.
It is a super-3 number, since 3×1411465074713 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141146507071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70573253735 + 70573253736.
It is an arithmetic number, because the mean of its divisors is an integer number (70573253736).
Almost surely, 2141146507471 is an apocalyptic number.
141146507471 is a deficient number, since it is larger than the sum of its proper divisors (1).
141146507471 is an equidigital number, since it uses as much as digits as its factorization.
141146507471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 94080, while the sum is 41.
The spelling of 141146507471 in words is "one hundred forty-one billion, one hundred forty-six million, five hundred seven thousand, four hundred seventy-one".
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