Base | Representation |
---|---|
bin | 10100100010100100100… |
… | …100001110010101010001 |
3 | 11222221100120112011222121 |
4 | 110202210210032111101 |
5 | 141111233104414101 |
6 | 3000234442534241 |
7 | 203656353004633 |
oct | 24424444162521 |
9 | 4887316464877 |
10 | 1411510232401 |
11 | 4a4688801255 |
12 | 1a9687b07381 |
13 | a3149459b89 |
14 | 4c463176a53 |
15 | 26ab38d90a1 |
hex | 148a490e551 |
1411510232401 has 2 divisors, whose sum is σ = 1411510232402. Its totient is φ = 1411510232400.
The previous prime is 1411510232393. The next prime is 1411510232449. The reversal of 1411510232401 is 1042320151141.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1368785342401 + 42724890000 = 1169951^2 + 206700^2 .
It is a cyclic number.
It is not a de Polignac number, because 1411510232401 - 23 = 1411510232393 is a prime.
It is a super-2 number, since 2×14115102324012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1411510232471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705755116200 + 705755116201.
It is an arithmetic number, because the mean of its divisors is an integer number (705755116201).
Almost surely, 21411510232401 is an apocalyptic number.
It is an amenable number.
1411510232401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1411510232401 is an equidigital number, since it uses as much as digits as its factorization.
1411510232401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 25.
Adding to 1411510232401 its reverse (1042320151141), we get a palindrome (2453830383542).
The spelling of 1411510232401 in words is "one trillion, four hundred eleven billion, five hundred ten million, two hundred thirty-two thousand, four hundred one".
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