14115131 has 2 divisors, whose sum is σ = 14115132. Its totient is φ = 14115130.

The previous prime is 14115113. The next prime is 14115139. The reversal of 14115131 is 13151141.

Together with previous prime (14115113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14115131 - 2⁶ = 14115067 is a prime.

It is a super-2 number, since 2×14115131² = 398473846294322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14115139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057565 + 7057566.

It is an arithmetic number, because the mean of its divisors is an integer number (7057566).

Almost surely, 2^14115131 is an apocalyptic number.

14115131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14115131 is an equidigital number, since it uses as much as digits as its factorization.

14115131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 60, while the sum is 17.

The square root of 14115131 is about 3757.0109129466. The cubic root of 14115131 is about 241.6730952445.

Adding to 14115131 its reverse (13151141), we get a palindrome (27266272).

The spelling of 14115131 in words is "fourteen million, one hundred fifteen thousand, one hundred thirty-one".