14115131497 has 2 divisors, whose sum is σ = 14115131498. Its totient is φ = 14115131496.

The previous prime is 14115131479. The next prime is 14115131531. The reversal of 14115131497 is 79413151141.

Together with previous prime (14115131479) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11130039001 + 2985092496 = 105499^2 + 54636^2 .

It is an emirp because it is prime and its reverse (79413151141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14115131497 - 2¹⁹ = 14114607209 is a prime.

It is a super-2 number, since 2×14115131497² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14115131897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057565748 + 7057565749.

It is an arithmetic number, because the mean of its divisors is an integer number (7057565749).

Almost surely, 2^14115131497 is an apocalyptic number.

It is an amenable number.

14115131497 is a deficient number, since it is larger than the sum of its proper divisors (1).

14115131497 is an equidigital number, since it uses as much as digits as its factorization.

14115131497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15120, while the sum is 37.

It can be divided in two parts, 14 and 115131497, that added together give a palindrome (115131511).

The spelling of 14115131497 in words is "fourteen billion, one hundred fifteen million, one hundred thirty-one thousand, four hundred ninety-seven".