Base | Representation |
---|---|
bin | 11010010010101001… |
… | …11101000001010111 |
3 | 1100102201002222021101 |
4 | 31021110331001113 |
5 | 212401433201404 |
6 | 10252344130531 |
7 | 1006533431551 |
oct | 151124750127 |
9 | 40381088241 |
10 | 14115131479 |
11 | 5a93695219 |
12 | 289b166a47 |
13 | 143c41cb07 |
14 | 97c8c64d1 |
15 | 5792c62a4 |
hex | 34953d057 |
14115131479 has 2 divisors, whose sum is σ = 14115131480. Its totient is φ = 14115131478.
The previous prime is 14115131473. The next prime is 14115131497. The reversal of 14115131479 is 97413151141.
14115131479 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with next prime (14115131497) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is an emirp because it is prime and its reverse (97413151141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14115131479 - 217 = 14115000407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14115131473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057565739 + 7057565740.
It is an arithmetic number, because the mean of its divisors is an integer number (7057565740).
Almost surely, 214115131479 is an apocalyptic number.
14115131479 is a deficient number, since it is larger than the sum of its proper divisors (1).
14115131479 is an equidigital number, since it uses as much as digits as its factorization.
14115131479 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15120, while the sum is 37.
The spelling of 14115131479 in words is "fourteen billion, one hundred fifteen million, one hundred thirty-one thousand, four hundred seventy-nine".
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