14115135405463 has 2 divisors, whose sum is σ = 14115135405464. Its totient is φ = 14115135405462.

The previous prime is 14115135405433. The next prime is 14115135405593. The reversal of 14115135405463 is 36450453151141.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14115135405463 is a prime.

It is a super-3 number, since 3×14115135405463³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14115135405433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057567702731 + 7057567702732.

It is an arithmetic number, because the mean of its divisors is an integer number (7057567702732).

Almost surely, 2^{14115135405463} is an apocalyptic number.

14115135405463 is a deficient number, since it is larger than the sum of its proper divisors (1).

14115135405463 is an equidigital number, since it uses as much as digits as its factorization.

14115135405463 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432000, while the sum is 43.

The spelling of 14115135405463 in words is "fourteen trillion, one hundred fifteen billion, one hundred thirty-five million, four hundred five thousand, four hundred sixty-three".