Base | Representation |
---|---|
bin | 1100110101100111000000… |
… | …0111011001111100011101 |
3 | 1211222101122121210000210010 |
4 | 3031121300013121330131 |
5 | 3322230303220233000 |
6 | 50004224000233433 |
7 | 2654533262224140 |
oct | 315316007317435 |
9 | 54871577700703 |
10 | 14115143524125 |
11 | 45522205a1586 |
12 | 16bb73900b879 |
13 | 7b508ac51b47 |
14 | 36b2687d4057 |
15 | 19727984cd50 |
hex | cd6701d9f1d |
14115143524125 has 128 divisors (see below), whose sum is σ = 27023005900800. Its totient is φ = 6409492953600.
The previous prime is 14115143524099. The next prime is 14115143524159. The reversal of 14115143524125 is 52142534151141.
It is not a de Polignac number, because 14115143524125 - 210 = 14115143523101 is a prime.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 256243336 + ... + 256298414.
It is an arithmetic number, because the mean of its divisors is an integer number (211117233600).
Almost surely, 214115143524125 is an apocalyptic number.
14115143524125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
14115143524125 is a deficient number, since it is larger than the sum of its proper divisors (12907862376675).
14115143524125 is a wasteful number, since it uses less digits than its factorization.
14115143524125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55756 (or 55746 counting only the distinct ones).
The product of its digits is 96000, while the sum is 39.
Adding to 14115143524125 its reverse (52142534151141), we get a palindrome (66257677675266).
The spelling of 14115143524125 in words is "fourteen trillion, one hundred fifteen billion, one hundred forty-three million, five hundred twenty-four thousand, one hundred twenty-five".
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