141152503501313 has 4 divisors (see below), whose sum is σ = 141162523569600. Its totient is φ = 141142483433028.

The previous prime is 141152503501259. The next prime is 141152503501357. The reversal of 141152503501313 is 313105305251141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141152503501313 - 2²⁶ = 141152436392449 is a prime.

It is a super-3 number, since 3×141152503501313³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141152503501363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5010013013 + ... + 5010041186.

It is an arithmetic number, because the mean of its divisors is an integer number (35290630892400).

Almost surely, 2^{141152503501313} is an apocalyptic number.

It is an amenable number.

141152503501313 is a deficient number, since it is larger than the sum of its proper divisors (10020068287).

141152503501313 is a wasteful number, since it uses less digits than its factorization.

141152503501313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10020068286.

The product of its (nonzero) digits is 27000, while the sum is 35.

Adding to 141152503501313 its reverse (313105305251141), we get a palindrome (454257808752454).

The spelling of 141152503501313 in words is "one hundred forty-one trillion, one hundred fifty-two billion, five hundred three million, five hundred one thousand, three hundred thirteen".