Base | Representation |
---|---|
bin | 11010010010101100… |
… | …00001000001110011 |
3 | 1100102201122010101021 |
4 | 31021112001001303 |
5 | 212402021110120 |
6 | 10252354120311 |
7 | 1006536001636 |
oct | 151126010163 |
9 | 40381563337 |
10 | 14115410035 |
11 | 5a93865531 |
12 | 289b280097 |
13 | 143c4b983c |
14 | 97c959c1d |
15 | 57932daaa |
hex | 349581073 |
14115410035 has 16 divisors (see below), whose sum is σ = 17114467392. Its totient is φ = 11175120000.
The previous prime is 14115409999. The next prime is 14115410041. The reversal of 14115410035 is 53001451141.
It is not a de Polignac number, because 14115410035 - 211 = 14115407987 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14115409991 and 14115410009.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1282777 + ... + 1293733.
It is an arithmetic number, because the mean of its divisors is an integer number (1069654212).
Almost surely, 214115410035 is an apocalyptic number.
14115410035 is a deficient number, since it is larger than the sum of its proper divisors (2999057357).
14115410035 is a wasteful number, since it uses less digits than its factorization.
14115410035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13614.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 14115410035 its reverse (53001451141), we get a palindrome (67116861176).
The spelling of 14115410035 in words is "fourteen billion, one hundred fifteen million, four hundred ten thousand, thirty-five".
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