Base | Representation |
---|---|
bin | 11010010010101100… |
… | …00100000101010111 |
3 | 1100102201122202112211 |
4 | 31021112010011113 |
5 | 212402022010201 |
6 | 10252354254251 |
7 | 1006536053266 |
oct | 151126040527 |
9 | 40381582484 |
10 | 14115422551 |
11 | 5a9387397a |
12 | 289b287387 |
13 | 143c4c2449 |
14 | 97c9605dd |
15 | 579332651 |
hex | 349584157 |
14115422551 has 4 divisors (see below), whose sum is σ = 14117057992. Its totient is φ = 14113787112.
The previous prime is 14115422543. The next prime is 14115422567. The reversal of 14115422551 is 15522451141.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15522451141 = 73 ⋅212636317.
It is a cyclic number.
It is not a de Polignac number, because 14115422551 - 23 = 14115422543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14115422521) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 804705 + ... + 822058.
It is an arithmetic number, because the mean of its divisors is an integer number (3529264498).
Almost surely, 214115422551 is an apocalyptic number.
14115422551 is a deficient number, since it is larger than the sum of its proper divisors (1635441).
14115422551 is an equidigital number, since it uses as much as digits as its factorization.
14115422551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1635440.
The product of its digits is 8000, while the sum is 31.
Adding to 14115422551 its reverse (15522451141), we get a palindrome (29637873692).
The spelling of 14115422551 in words is "fourteen billion, one hundred fifteen million, four hundred twenty-two thousand, five hundred fifty-one".
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