Base | Representation |
---|---|
bin | 11010010010101100… |
… | …11001101101011101 |
3 | 1100102201211021001122 |
4 | 31021112121231131 |
5 | 212402032324013 |
6 | 10252400220325 |
7 | 1006536602453 |
oct | 151126315535 |
9 | 40381737048 |
10 | 14115511133 |
11 | 5a93924489 |
12 | 289b30a6a5 |
13 | 143c523869 |
14 | 97c9849d3 |
15 | 57934da08 |
hex | 349599b5d |
14115511133 has 2 divisors, whose sum is σ = 14115511134. Its totient is φ = 14115511132.
The previous prime is 14115511121. The next prime is 14115511231. The reversal of 14115511133 is 33111551141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9703629049 + 4411882084 = 98507^2 + 66422^2 .
It is an emirp because it is prime and its reverse (33111551141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14115511133 - 210 = 14115510109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14115510133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057755566 + 7057755567.
It is an arithmetic number, because the mean of its divisors is an integer number (7057755567).
Almost surely, 214115511133 is an apocalyptic number.
It is an amenable number.
14115511133 is a deficient number, since it is larger than the sum of its proper divisors (1).
14115511133 is an equidigital number, since it uses as much as digits as its factorization.
14115511133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 900, while the sum is 26.
The spelling of 14115511133 in words is "fourteen billion, one hundred fifteen million, five hundred eleven thousand, one hundred thirty-three".
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