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1411824650323 is a prime number
BaseRepresentation
bin10100100010110111010…
…011101000100001010011
311222222011111011021021211
4110202313103220201103
5141112404102302243
63000325554000551
7204000221344153
oct24426723504123
94888144137254
101411824650323
114a482a23307a
121a9755276157
13a3199635399
144c492c20763
1526ad12e4d9d
hex148b74e8853

1411824650323 has 2 divisors, whose sum is σ = 1411824650324. Its totient is φ = 1411824650322.

The previous prime is 1411824650321. The next prime is 1411824650359. The reversal of 1411824650323 is 3230564281141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1411824650323 - 21 = 1411824650321 is a prime.

It is a super-2 number, since 2×14118246503232 (a number of 25 digits) contains 22 as substring.

Together with 1411824650321, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1411824650321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705912325161 + 705912325162.

It is an arithmetic number, because the mean of its divisors is an integer number (705912325162).

Almost surely, 21411824650323 is an apocalyptic number.

1411824650323 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411824650323 is an equidigital number, since it uses as much as digits as its factorization.

1411824650323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 40.

The spelling of 1411824650323 in words is "one trillion, four hundred eleven billion, eight hundred twenty-four million, six hundred fifty thousand, three hundred twenty-three".