14120031433 has 4 divisors (see below), whose sum is σ = 14122677520. Its totient is φ = 14117385348.

The previous prime is 14120031413. The next prime is 14120031439. The reversal of 14120031433 is 33413002141.

14120031433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33413002141 = 353 ⋅94654397.

It is a cyclic number.

It is not a de Polignac number, because 14120031433 - 2⁹ = 14120030921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14120031439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1315023 + ... + 1325716.

It is an arithmetic number, because the mean of its divisors is an integer number (3530669380).

Almost surely, 2^14120031433 is an apocalyptic number.

It is an amenable number.

14120031433 is a deficient number, since it is larger than the sum of its proper divisors (2646087).

14120031433 is an equidigital number, since it uses as much as digits as its factorization.

14120031433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2646086.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 14120031433 its reverse (33413002141), we get a palindrome (47533033574).

The spelling of 14120031433 in words is "fourteen billion, one hundred twenty million, thirty-one thousand, four hundred thirty-three".