141201041433511 has 2 divisors, whose sum is σ = 141201041433512. Its totient is φ = 141201041433510.

The previous prime is 141201041433497. The next prime is 141201041433577. The reversal of 141201041433511 is 115334140102141.

It is a weak prime.

It is an emirp because it is prime and its reverse (115334140102141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141201041433511 - 2¹⁵ = 141201041400743 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141201041463511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70600520716755 + 70600520716756.

It is an arithmetic number, because the mean of its divisors is an integer number (70600520716756).

Almost surely, 2^{141201041433511} is an apocalyptic number.

141201041433511 is a deficient number, since it is larger than the sum of its proper divisors (1).

141201041433511 is an equidigital number, since it uses as much as digits as its factorization.

141201041433511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 141201041433511 its reverse (115334140102141), we get a palindrome (256535181535652).

The spelling of 141201041433511 in words is "one hundred forty-one trillion, two hundred one billion, forty-one million, four hundred thirty-three thousand, five hundred eleven".